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If A=[[2, 0, -1], [3, 1, 2], [-1, 1, 2]]...

If `A=[[2, 0, -1], [3, 1, 2], [-1, 1, 2]]`, then adjA=

A

`[[0, -8, 4], [-1, 3, -2], [1, -7, 2]]`

B

`[[0, -1, 1], [8, 2, -7], [4, -2, 2]]`

C

`[[0, -1, 1], [-8, 3, -7], [4, -2, 2]]`

D

`[[0, -1, -1], [-8, 3, -7], [4, -2, 2]]`

Text Solution

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The correct Answer is:
C
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  9. If A=[[3, 4], [5, 7]], then A(adjA)=

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  11. If A=[[cosalpha, sinalpha], [-sinalpha, cosalpha]] and A(adjA)=[[k, 0]...

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  15. If A is a square matrix of order 2times2 and |A|=5, then |A(adjA)|=

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