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If A=[[0, 1, -1], [2, 1, 3], [3, 2, 1]],...

If `A=[[0, 1, -1], [2, 1, 3], [3, 2, 1]]`, then `(A(adjA)A^(-1))A=`

A

`2[[3, 0,0], [0, 3, 0], [0, 0, 3]]`

B

`[[-6, 0, 0], [0, -6, 0], [0, 0, -6]]`

C

`(1)/(6)[[0, 1, -1], [2, 1, 3], [3, 2, 1]]`

D

`[[3, 0, 0], [0, 3, 0], [0, 0, 3]]`

Text Solution

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The correct Answer is:
A
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