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If A=[[0, 3], [2, 0]] and A^(-1)=lambda(...

If `A=[[0, 3], [2, 0]] and A^(-1)=lambda(adjA)`, then `lambda=`

A

`-(1)/(6)`

B

`-(1)/(3)`

C

`(1)/(3)`

D

`(1)/(6)`

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The correct Answer is:
A
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