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If A=[[cosalpha, -sinalpha, 0], [sinalph...

If `A=[[cosalpha, -sinalpha, 0], [sinalpha, cosalpha, 0], [0, 0, 1]]`, then `(adjA)^(-1)=`

A

`[[cosalpha, -sinalpha, 0], [sinalpha, cosalpha, 0], [0, 0, 1]]`

B

`[[-cosalpha, sinalpha, 0], [sinalpha, -cosalpha, 0], [0, 0, 1]]`

C

`[[-cosalpha, sinalpha, 0], [sinalpha, cosalpha, 0], [0, 0, 1]]`

D

`[[cosalpha, sinalpha, 0], [-sinalpha, cosalpha, 0], [0, 0, 1]]`

Text Solution

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The correct Answer is:
A
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