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The inverse of matrix [[2, 1], [7, 4]] i...

The inverse of matrix `[[2, 1], [7, 4]]` is

A

`-[[4, 1], [7, 2]]`

B

`[[4, 1], [7, 2]]`

C

`-[[4, -1], [-7, 2]]`

D

`[[4, -1], [-7, 2]]`

Text Solution

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The correct Answer is:
To find the inverse of the matrix \(\begin{bmatrix} 2 & 1 \\ 7 & 4 \end{bmatrix}\), we will follow these steps: ### Step 1: Calculate the Determinant of the Matrix The determinant of a \(2 \times 2\) matrix \(\begin{bmatrix} a & b \\ c & d \end{bmatrix}\) is calculated using the formula: \[ \text{det}(A) = ad - bc \] For our matrix \(A = \begin{bmatrix} 2 & 1 \\ 7 & 4 \end{bmatrix}\): - \(a = 2\) - \(b = 1\) - \(c = 7\) - \(d = 4\) Calculating the determinant: \[ \text{det}(A) = (2)(4) - (1)(7) = 8 - 7 = 1 \] ### Step 2: Calculate the Cofactor Matrix The cofactor matrix is obtained by applying the sign convention and calculating the minors of each element. The sign convention for a \(2 \times 2\) matrix is: \[ \begin{bmatrix} + & - \\ - & + \end{bmatrix} \] Calculating the cofactors: - For element \(2\) (position (1,1)), the minor is \(4\) (since we remove the first row and first column). - For element \(1\) (position (1,2)), the minor is \(7\) (remove first row and second column, sign is negative). - For element \(7\) (position (2,1)), the minor is \(1\) (remove second row and first column, sign is negative). - For element \(4\) (position (2,2)), the minor is \(2\) (remove second row and second column). Thus, the cofactor matrix \(C(A)\) is: \[ C(A) = \begin{bmatrix} 4 & -1 \\ -7 & 2 \end{bmatrix} \] ### Step 3: Calculate the Adjoint of the Matrix The adjoint of a matrix is the transpose of the cofactor matrix. So we need to transpose \(C(A)\): \[ \text{adj}(A) = C(A)^T = \begin{bmatrix} 4 & -7 \\ -1 & 2 \end{bmatrix} \] ### Step 4: Calculate the Inverse of the Matrix Using the formula for the inverse of a matrix: \[ A^{-1} = \frac{1}{\text{det}(A)} \cdot \text{adj}(A) \] Substituting the values we found: \[ A^{-1} = \frac{1}{1} \cdot \begin{bmatrix} 4 & -7 \\ -1 & 2 \end{bmatrix} = \begin{bmatrix} 4 & -7 \\ -1 & 2 \end{bmatrix} \] ### Final Answer The inverse of the matrix \(\begin{bmatrix} 2 & 1 \\ 7 & 4 \end{bmatrix}\) is: \[ \begin{bmatrix} 4 & -7 \\ -1 & 2 \end{bmatrix} \] ---
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