Inverse of the matrix A=[[cos2theta, -si...

Inverse of the matrix `A=[[cos2theta, -sin2theta], [sin2theta, cos2theta]]` is

A

`[[cos2theta, sin2theta], [sin2theta, cos2theta]]`

B

`[[cos2theta, sin2theta], [-sin2theta, cos2theta]]`

C

`[[cos2theta, -sin2theta], [sin2theta, cos2theta]]`

D

`[[cos2theta, sin2theta], [sin2theta, -cos2theta]]`

Text Solution

Verified by Experts

The correct Answer is:

B

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Knowledge Check

Inverse of the matrix [(cos 2 theta,-sin 2theta),(sin 2 theta, cos 2theta)] is

A

`[(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta)]`

B

`[(cos 2 theta, sin 2theta),(sin 2 theta, -cos 2 theta)]`

C

`[(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta)]`

D

`[(cos 2 theta, sin 2 theta),(-sin 2 theta, cos 2 theta)]`

Inverse of the matrix [{:(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta):}] is

A

`[{:(cos 2 theta, -sin 2 theta),(sin 2 theta, cos 2 theta):}]`

B

`[{:(cos 2 theta, sin 2 theta),(sin 2 theta, -cos 2 theta):}]`

C

`[{:(cos 2 theta, sin 2 theta),(sin 2 theta, cos 2 theta):}]`

D

`[{:(cos 2 theta, sin 2 theta),(-sin 2 theta, cos 2 theta):}]`

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