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If A=[[1, 0, 0], [0, 1, 1], [0, -2, 4]] ...

If `A=[[1, 0, 0], [0, 1, 1], [0, -2, 4]] and A^(-1)=(1)/(6)(A^(2)+cA+dI)`, where `c, din R` and I is an identity matrix of order 3, then (c, d)=

A

`(-6, -11)`

B

`(-6, 11)`

C

`(6, -11)`

D

`(6, 11)`

Text Solution

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The correct Answer is:
B
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