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If P(X=x)={{:((x^(2))/(5)","x=0","1","2)...

If `P(X=x)={{:((x^(2))/(5)","x=0","1","2),(0","" otherwise"):},"then"`

A

`underset(x_(i)=S)sumP(X=x)ne1`

B

`underset(x_(i)=S)sumP(X=x)=2`

C

f is not a p.m.f.

D

f is a p.m.f.

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The correct Answer is:
D
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