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If P(X=x)={{:((x-1)/(3)","x=1","2","3),(...

If `P(X=x)={{:((x-1)/(3)","x=1","2","3),(0", otherwise"):},"then"`

A

`underset(x_(i)=S)sumP(X=x)ne1`

B

`underset(x_(i)=S)sumP(X=x)=2`

C

f is a p.m.f.

D

f is not a p.m.f.

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The correct Answer is:
C
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