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A player tosses 2 fair coins. He wins Rs...

A player tosses 2 fair coins. He wins Rs. 5 if 2 heads appear, Rs. 2 if 1 head appear and Rs. 1 if no head appears, then variance of his winning amount is

A

Rs. 1.25

B

Rs. 2.15

C

Rs. 2.5

D

Rs. 2.25

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The correct Answer is:
D
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NIKITA PUBLICATION-PROBABILITY DISTRIBUTION-MCQs
  1. The p.m.f. of a r.v. X is P(x)={{:((1)/(15)","x=1","2","…","15),(0", o...

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  2. A players tosses 2 fair coins. He wins Rs. 5 if 2 heads appear, Rs. 2 ...

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  3. A player tosses 2 fair coins. He wins Rs. 5 if 2 heads appear, Rs. 2 i...

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  4. For the p.m.f. P (X = x) of discrete random variable X which takes val...

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  5. The p.d.f. of continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

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  6. The p.d.f. of continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

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  7. The p.d.f. of continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

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  8. It is known that error in experiment of reaction temperature ("in """^...

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  9. It is known that error in experiment of reaction temperature ("in """^...

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  10. It is known that error in experiment of reaction temperature ("in """^...

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  11. If f(x)={{:((x)/(2)", for"-2ltxlt2).(0", otherwise"):}, then

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  12. If f(x)={{:((e^(-x)","0ltxltoo),(0", otherwise"):}, then

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  13. The p.d.f. of a r.v. X is f(x)={{:((1)/(x^(2))","1ltxltoo),(0", otherw...

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  14. The p.d.f. of a continuous r.v. X is f(x)={{:((x^(2))/(3)","-1ltxlt2...

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  15. The p.d.f. of a continuous r.v. X is f(x)={{:((x^(2))/(3)","-1ltxlt2...

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  16. The p.d.f. of a continuous r.v. X is f(x)={{:((x^(2))/(3)","-1lt x lt...

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  17. The p.d.f. of a continuous r.v. X is f(x)={{:((x^(2))/(3)","-1lt x lt ...

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  18. The p.d.f. of a continuous r.v. X is f(x)={{:((x^(2))/(3)","-1lt x lt...

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  19. The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise"):...

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  20. The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise")...

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