Home
Class 12
MATHS
Let X = time (in minutes) that elapses b...

Let X = time (in minutes) that elapses between the bell and the end of the lecture in case of a college professor. If X has p.d.f. `f(x)={{:(kx^(2)","0lexle2),(0", otherwise"):}`, then k =

A

`(8)/(3)`

B

`(3)/(8)`

C

`(4)/(3)`

D

`(3)/(4)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PLANE

    NIKITA PUBLICATION|Exercise MULTIOLE CHOICE QUESTIONS|154 Videos
  • QUESTION PAPER MHT-CET 2016

    NIKITA PUBLICATION|Exercise MCQs|50 Videos

Similar Questions

Explore conceptually related problems

Let X = time (in minutes ) that lapses between the bell and the end of the lectures in cases of a collge professor. Suppose X has p.d.f f(x) ={{:(kx^(2),0 le x le 2),(0,"otherwise"):} What is the probability that lecture ends within 1 minute of the bell ringing ?

Let X = time (in minutes ) that lapses between the bell and the end of the lectures in cases of a collge professor. Suppose X has p.d.f f(x) ={{:(kx^(2),0 le x le 2),(0,"otherwise"):} Find the value of k.

Let the random variable X is defined as time (in minutes) that elapses between the bell and end of the lecture in case of collagen professor whrer pdf is defined as f(x)={{:(kx^2","0lexlt2),(0", ""elsewhere"):} find the probability that lecture continue for atleast 90s beyond the bell

The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):} , then k =

The p.d.f. of a continuous r.v. X is f(x)={{:(k(4-x^(2))","-2lexle2),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", otherwise"):} , then k =

The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise"):} , then P(|X|lt1) =

NIKITA PUBLICATION-PROBABILITY DISTRIBUTION-MCQs
  1. The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise")...

    Text Solution

    |

  2. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(10)","-5lexle5),(0"...

    Text Solution

    |

  3. Let X = time (in minutes) that elapses between the bell and the end of...

    Text Solution

    |

  4. Let X = time (in minutes ) that lapses between the bell and the e...

    Text Solution

    |

  5. Let the random variable X is defined as time (in minutes) that elapses...

    Text Solution

    |

  6. The p.d.f. of a r.v. X is f(x)={{:((1)/(x^(2))","1ltxltoo),(0", otherw...

    Text Solution

    |

  7. The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):}, t...

    Text Solution

    |

  8. The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):}, t...

    Text Solution

    |

  9. The p.d.f. of X is f(x)={{:((x+2)/(18)","-2ltxlt4),(0", otheriwse"):},...

    Text Solution

    |

  10. The p.d.f. of X is f(x)={{:((x+2)/(18)","-2ltxlt4),(0", otherwise"):},...

    Text Solution

    |

  11. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)", "0ltxlt4),(0"...

    Text Solution

    |

  12. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  13. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  14. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  15. The p.d.f. of a r.v. X is f(x)={{:(2x", "0lexle1),(0", otherwise"):},...

    Text Solution

    |

  16. The p.d.f. of a r.v. X is f(x)={{:(0.5x","0ltxlt2),(0", otherwise"):},...

    Text Solution

    |

  17. The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):}...

    Text Solution

    |

  18. The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):}...

    Text Solution

    |

  19. The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwi...

    Text Solution

    |

  20. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |