Home
Class 12
MATHS
Let the random variable X is defined as ...

Let the random variable X is defined as time (in minutes) that elapses between the bell and end of the lecture in case of collagen professor whrer pdf is defined as `f(x)={{:(kx^2","0lexlt2),(0", ""elsewhere"):}`
find the probability that lecture continue for atleast 90s beyond the bell

A

`(37)/(192)`

B

`(37)/(32)`

C

`(37)/(24)`

D

`(37)/(64)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • PLANE

    NIKITA PUBLICATION|Exercise MULTIOLE CHOICE QUESTIONS|154 Videos
  • QUESTION PAPER MHT-CET 2016

    NIKITA PUBLICATION|Exercise MCQs|50 Videos

Similar Questions

Explore conceptually related problems

Let X = time (in minutes) that elapses between the bell and the end of the lecture in case of a college professor. If X has p.d.f. f(x)={{:(kx^(2)","0lexle2),(0", otherwise"):} , then k =

Let X = time (in minutes ) that lapses between the bell and the end of the lectures in cases of a collge professor. Suppose X has p.d.f f(x) ={{:(kx^(2),0 le x le 2),(0,"otherwise"):} What is the probability that lecture ends within 1 minute of the bell ringing ?

Let X = time (in minutes ) that lapses between the bell and the end of the lectures in cases of a collge professor. Suppose X has p.d.f f(x) ={{:(kx^(2),0 le x le 2),(0,"otherwise"):} Find the value of k.

The pdf of a discrete random variable is defined as f(x)={{:(kx^2","0lexle6),(0", ""elsewhere"):} Then the value of F(4) is

If the p.d.f. of a c.r.v. X is f(x)={(kx^2 (1-x^3)","0lexle1,),(0",",elsewhere):} then :k…

Examine the differentiability of f , where f is defined by f(x) = {{:(x[x],if0lexlt2),((x-1)x,if2lexlt3):} at x = 2

Examine the differentiability of f, where f is defined by f(x) = {{:(x[x],if0lexlt2),((x-1)x,if2lexlt3):} at x = 2

Find k, if the following is p.d.f or r.v.f X. f(x) = {{:(kx^(2)(1-x), 0 lt x lt 1),(0, "otherwise"):}

If a random variable waiting time in minutes for bus and probability density function of x is given by f(x)={{:(1/5","0lexle5),(0",""otherwise"):} Then probability of waiting time not more than 4 minutes is equal to

Discuss the continuity of the function defined by f(x)={x+2, if x 0

NIKITA PUBLICATION-PROBABILITY DISTRIBUTION-MCQs
  1. Let X = time (in minutes) that elapses between the bell and the end of...

    Text Solution

    |

  2. Let X = time (in minutes ) that lapses between the bell and the e...

    Text Solution

    |

  3. Let the random variable X is defined as time (in minutes) that elapses...

    Text Solution

    |

  4. The p.d.f. of a r.v. X is f(x)={{:((1)/(x^(2))","1ltxltoo),(0", otherw...

    Text Solution

    |

  5. The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):}, t...

    Text Solution

    |

  6. The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):}, t...

    Text Solution

    |

  7. The p.d.f. of X is f(x)={{:((x+2)/(18)","-2ltxlt4),(0", otheriwse"):},...

    Text Solution

    |

  8. The p.d.f. of X is f(x)={{:((x+2)/(18)","-2ltxlt4),(0", otherwise"):},...

    Text Solution

    |

  9. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)", "0ltxlt4),(0"...

    Text Solution

    |

  10. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  11. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  12. The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)","0ltxlt4),(0", ...

    Text Solution

    |

  13. The p.d.f. of a r.v. X is f(x)={{:(2x", "0lexle1),(0", otherwise"):},...

    Text Solution

    |

  14. The p.d.f. of a r.v. X is f(x)={{:(0.5x","0ltxlt2),(0", otherwise"):},...

    Text Solution

    |

  15. The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):}...

    Text Solution

    |

  16. The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):}...

    Text Solution

    |

  17. The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwi...

    Text Solution

    |

  18. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |

  19. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |

  20. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |