Home
Class 12
MATHS
The p.d.f. of a r.v. X is f(x)={{:("ke"^...

The p.d.f. of a r.v. X is `f(x)={{:("ke"^(-thetax)","0lexltoo),(0", otherwise"):}`, then k =

A

`(1)/(theta)`

B

`(1)/(20)`

C

`theta`

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • PLANE

    NIKITA PUBLICATION|Exercise MULTIOLE CHOICE QUESTIONS|154 Videos

  • QUESTION PAPER MHT-CET 2016

    NIKITA PUBLICATION|Exercise MCQs|50 Videos

Similar Questions

Explore conceptually related problems

The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", otherwise"):} , then P(0ltXltM)=(1)/(2) , if M =

The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", otherwise"):} , then P(Xgt(1)/(theta)) =

The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f(x)={{:((1)/(x^(2))","1ltxltoo),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then P(Xle2) =

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then c.d.f. of X is

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then P(X ge 1) =

NIKITA PUBLICATION-PROBABILITY DISTRIBUTION-MCQs
  1. The p.d.f. of a r.v. X is f(x)={{:(0.5x", "0ltxlt2),(0", otherwise"):}...

    Text Solution

    |

  2. The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwi...

    Text Solution

    |

  3. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |

  4. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |

  5. The p.d.f. of a r.v. X is f(x)={{:("ke"^(-thetax)","0lexltoo),(0", oth...

    Text Solution

    |

  6. The p.d.f. of a r.v. X is f(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwis...

    Text Solution

    |

  7. The p.d.f. of a r.v. X is f(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwis...

    Text Solution

    |

  8. The p.d.f. of a r.v. X is f(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwis...

    Text Solution

    |

  9. The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwi...

    Text Solution

    |

  10. The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwi...

    Text Solution

    |

  11. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  12. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  13. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  14. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  15. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  16. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a",...

    Text Solution

    |

  17. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a","...

    Text Solution

    |

  18. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a","...

    Text Solution

    |

  19. Suppose r.v. X = waiting time in minutes for a bus and its p.d.f. is g...

    Text Solution

    |

  20. Suppose r.v. X = waiting time in minutes for a bus and its p.d.f. is g...

    Text Solution

    |