Home
Class 12
MATHS
The time (in minutes) for a lab assistan...

The time (in minutes) for a lab assistant to prepare the equipment for a certain experiment is a random variable taking values between 25 and 35 minutes with p.d.f. `f(x)={{:((1)/(10)","25lexle35),(0", otherwise"):}`, then F (x) =

A

`(25-x)/(10)`

B

`(x-25)/(10)`

C

`(25-x)/(5)`

D

`(x-25)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PLANE

    NIKITA PUBLICATION|Exercise MULTIOLE CHOICE QUESTIONS|154 Videos

  • QUESTION PAPER MHT-CET 2016

    NIKITA PUBLICATION|Exercise MCQs|50 Videos

Similar Questions

Explore conceptually related problems

The time (in minutes) for a lab assistant to prepare the equipment for a certain experiment is a random variable taking values between 25 and 35 minutes with p.d.f. f(x)={{:((1)/(10)","25lexle35),(0", otherwise"):} , then the probability that preparation time exceeds 33 minutes is

The time (in minutes) for a lab assistant to prepare the equipment for a certain experiment is a random variable taking values between 25 and 35 minutes with p.d.f f(x) = {{:((1)/(10), 25 le x le 35),(0, "otherwise"):} What is the probability that preparation time exceeds 33 minutes ? . Also find the c.d.f of X.

The p.d.f. of X is f(x)={{:((x+2)/(18)","-2ltxlt4),(0", otherwise"):} , then P(|X|lt1) =

The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise"):} , then P(|X|lt1) =

The p.d.f. of X is f(x)={{:((x^(2))/(18)","-3ltxlt3),(0", otherwise"):} , then P(X lt 1) =

The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(10)","-5lexle5),(0", otherwise"):} , then P(X lt0) =

The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(10)","-5lexle5),(0", otherwise"):} , then P(X lt0) =

The p.d.f. of a r.v. X is f(x)={{:((1)/(x^(2))","1ltxltoo),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a continuous r.v. X is f(x)={{:((x)/(8)", "0ltxlt4),(0", otherwise"):} , then F (x) =

NIKITA PUBLICATION-PROBABILITY DISTRIBUTION-MCQs
  1. The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwi...

    Text Solution

    |

  2. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  3. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  4. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  5. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  6. The p.d.f. of a r.v. X is f(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", ot...

    Text Solution

    |

  7. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a",...

    Text Solution

    |

  8. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a","...

    Text Solution

    |

  9. The p.d.f. of a continuous r.v. X is f(x)={{:((1)/(2a)","0ltxlt2a","...

    Text Solution

    |

  10. Suppose r.v. X = waiting time in minutes for a bus and its p.d.f. is g...

    Text Solution

    |

  11. Suppose r.v. X = waiting time in minutes for a bus and its p.d.f. is g...

    Text Solution

    |

  12. If a random variable waiting time in minutes for bus and probability d...

    Text Solution

    |

  13. The p.d.f. of a continuous r.v. X is f(x)={{:(k(4-x^(2))","-2lexle2),...

    Text Solution

    |

  14. The p.d.f. of a continuous r.v. X is f(x)={{:(k(4-x^(2))","-2lexle2),...

    Text Solution

    |

  15. The p.d.f. of a continuous r.v. X is f(x)={{:(k(4-x^(2))","-2lexle2)...

    Text Solution

    |

  16. The p.d.f. of a continuous r.v. X is f(x)={{:(k(4-x^(2))","-2lexle2),(...

    Text Solution

    |

  17. The time (in minutes) for a lab assistant to prepare the equipment for...

    Text Solution

    |

  18. The time (in minutes) for a lab assistant to prepare the equipment for...

    Text Solution

    |

  19. A boy tosses faiir coin 3 times. If he gets Rs 2X for X heads, then hi...

    Text Solution

    |

  20. A box contains 6 pens , 2 of which are defective Two pens are...

    Text Solution

    |