A wire of length 3 m connected in the left gap of a metre bridge balances a `8 Omega` resistance in the right gap at a point, which divides the bridge wire in the ratio of `3 :2` . What is the length of the wire corresponding to a resistance of the length of the wire corresponding to a resistance of `1 Omega` ?

Options

A. 1m
B. 0.75 m
C. 0.5 m
D. 0.25 m

Answer

D

Explanation

`(X)/(8)=(3)/(2) therefore X=(24)/(2) =12 Omega`
For a resistance of `12 Omega`, the length =3 m
`therefore` For a resistance of `1 Omega`, length `=(1)/(4)m`