In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then

Options

A. `I_(R )=I_(G)`
B. `I_(P) = I_(G)`
C. `I_(Q)=I_(G)`
D. `I_(Q)=I_(R )`

Answer

A

Explanation

`P ne R`
The reading of the galvanometer is the same, whether the switch S is open or closed. This means that no current flows through the branch BD i.e. `V_(B)= V_(D)` and the Wheatstone's network is balanced.
`therefore I_(P)=I_(Q) and I_(R )=I_(G)`
`therefore` (a) is the correct option.