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For a cell of e.m.f. 2 V , a balance is ...

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a `2Omega` resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

A

`0.25 Omega`

B

`0.5 Omega`

C

`0.75 Omega`

D

`1.00 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`r=R [(l_(1)-l_(2))/(l_(2))]=2xx(10)/(40)=0.5 Omega`
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