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A radiostation broadcasts at frequency o...

A radiostation broadcasts at frequency of 100 MHz. If the radiating power of the transmitter is 66.6 KW, then the number of photons radiated per second is
[ Take `h=6.66xx10^(-34)Js` ]

A

`66.6xx10^(20)`

B

`10^(30)`

C

`2xx10^(30)`

D

`10^(28)`

Text Solution

Verified by Experts

The correct Answer is:
B
Power `= 66.6KW=66.6xx10^(3)W=66.6xx10^(3)J//s`
`v=100 MHz=100xx10^(6)=10^(8)=Hz`
Energy of photon `=hv " " :.` Total energy `=` nhv
`n=(E)/(hv)=(66.6xx10^(3))/(6.66xx10^(-34)xx10^(8))=10^(30)`
no. of photons radiated/sec `=10^(30)`
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MARVEL PUBLICATION-ELECTRONS AND PHOTONS -TEST YOUR GRASP - 17
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