A source `S_(1)` is producing `10^(15)` photons/s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))/("power of" S_(1))` is equal to

Options

A. 1
B. 1.1
C. 1.04
D. 0.98

Answer

A

Explanation

Power of source `= E/t = (nhv)/(t)= Nhv= (Nhc)/(lambda)`
where `N= `No. of photons emitted/sec.
`:. (P_(2))/(P_(1))=(N_(2)hc)/(lambda_(2))xx (lambda_(1))/(N_(1)hc)`
`=(lambda_(1)N_(2))/(N_(1)lambda_(2))= (5000xx10^(-10)xx1.02xx10^(15))/(10^(5)xx5100xx10^(-10))`
`=(50xx1.02)/(51)=1`