A radio transmitter operates at a frequency of `880 kHz` and a power of `10 kW`. The number of photons emitted per second are

Options

A. `1.5xx10^(25)`
B. `1.6xx10^(30)`
C. `1.72xx10^(31)`
D. `2.8xx10^(30)`

Answer

C

Explanation

Frequency of the transmitter `(v)=880 Kz=880xx10^(3) Hz`
Power of the transmitter `= 10 kW=10xx10^(3)=10^(4)W`
But power `=("Work")/("Time")=("Energy")/("Time")`
But by Planck's law E `=` hv and for n photons, E `=` nhv
`:.P=(nhv)/(t)` if N `=` no. of photons emitted/s, then `N=n/t`
`:.P=Nhv`
`:.N=(P)/(hv)=(10^(4))/(6.63xx10^(-34)xx880xx10^(3))`
`=1.72xx10^(31)`