A red bulb and violet bulb of equal power emits `n_(R )` and `n_(v)` number of photons in a given time, then

Options

A. `n_(R) lt n_(V)`
B. `n_(R) ge n_(V)`
C. `n_(R) gt n_(V)`
D. `n_(R)=n_(V)`

Answer

C

Explanation

In the visible spectrum, `v_("Violet" )gt v_("Red")`

For a photon `E=hv` and `P=E/t`
If the power of each photon is P then the energy given out in one second is Pt . If n is the number of photons,
`n=(Pt)/(E)=(Pt)/(hv)`
For red, `n_(R)=(Pt)/(hv_(R))` and `n_(v)=(Pt)/(hv_(v))`
`:.(n_(R))/(n_(v))=(v_(V))/(v_(R)) :'` Both have the same power
`:'v_(V) gt v_(R) :.n_(R) gt n_(V)`