The work function of a photoelectric met...

The work function of a photoelectric metal is 3.31 eV. If `h=6.62xx10^(-34)Js`, then its threshold frequency will be

`8xx10^(14)` Hz

`8xx10^(10)`Hz

`5xx10^(15)` Hz

`3xx10^(14)` Hz

Text Solution

Verified by Experts

The correct Answer is:

`v_(0)=(W_(0))/(h)=(3.31xx1.6xx10^(-19))/(6.62xx10^(-34))`
`v_(0)=0.8xx10^(15)=8xx10^(14)`Hz

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MARVEL PUBLICATION-ELECTRONS AND PHOTONS -TEST YOUR GRASP - 17

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