When photons of energy hv fall on a metal plate, having a work function W, the maximum kinetic energy of the ejected photo electrons is K. What will be the maximum K.E. of the ejected photo electrons, from the same plate if the frequency of incident radiation is doubled ?

Options

A. 2 K
B. `K/2`
C. `hv+K`
D. `K=W_(0)`

Answer

C

Explanation

`hv=W_(0)+K" " :.K=hv-W_(0)`
`K'=2hv-W_(0)=hv+(hv-W_(0))`
`:.K'=hv+K`