A photocell is illuminated by a point source of light kept at a distance of 50 cm. If the source is shifted by 50 cm away from the photocell, then

Options

A. energy of each emitted photoelectron will be half of the initial energy
B. energy of each photoelectron will be two times the initial energy
C. number of emitted photoelectrons will be one quarter on the initial number
D. number of emitted photoelectrons will be double the initial number

Answer

C

Explanation

`(I_(2))/(I_(1))=(d_(1)^(2))/(d_(2)^(2))=((50)/(100))^(2)=1/4`