For light of a wavelength 4000 Å, the p...

For light of a wavelength 4000 Å, the photon energy is 2eV. For X rays of wavelength 1 Å, the photon energy will be

A

2000 eV

B

4000 eV

C

6000 eV

D

8000 eV

Verified by Experts

The correct Answer is:

D

`E=(hC)/(lambda):.(E_(1))/(E_(2))=(lambda_(2))/(lambda_(1))=(1)/(4000)`
`:.E_(2)=4000xx2=8000 eV`

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