There are `N_(1)` photons of frequency `v_(1)`, in a beam of light, In another light beam of equal energy there are `N_(2)` photons of frequency `v_(2)`. Then `N_(1)` and `N_(2)` are related as

Options

A. `(N_(1))/(N_(2))=1`
B. `(N_(1))/(N_(2))=(v_(1))/(v_(2))`
C. `(N_(1))/(N_(2))=(v_(2))/(v_(1))`
D. `(N_(1))/(N_(2))=sqrt((v_(2))/(v_(1)))`

Answer

C

Explanation

Since they have same energy, `E_(1)=E_(2)`
`:.N_(1)hv_(1)=N_(2)hv_(2)" " :.(N_(1))/(N_(2))=(v_(2))/(v_(1))`