The momentum of a photon of electromagnetic radiation is `3.3xx10^(-29)` kg m/s . The frequency of radiation is
`[h=6.6xx10^(-34)Js]`

Options

A. `2.5xx10^(15)` Hz
B. `1.5xx10^(13)` Hz
C. `6xx10^(13)` Hz
D. `5xx10^(15)` Hz

Explanation

To find the frequency of the photon given its momentum and Planck's constant, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between momentum, frequency, and Planck's constant**:
The momentum \( P \) of a photon can be expressed in terms of its frequency \( \nu \) and Planck's constant \( h \) as:
\[ P = \frac{h \nu}{c} \]
where \( c \) is the speed of light.

2. **Rearranging the formula to find frequency**:
We can rearrange the formula to solve for frequency \( \nu \):
\[ \nu = \frac{P c}{h} \]

3. **Substituting the known values**:
We know:
- \( P = 3.3 \times 10^{-29} \, \text{kg m/s} \)
- \( c = 3 \times 10^8 \, \text{m/s} \) (speed of light)
- \( h = 6.6 \times 10^{-34} \, \text{Js} \) (Planck's constant)

Plugging these values into the equation for frequency:
\[ \nu = \frac{(3.3 \times 10^{-29} \, \text{kg m/s}) \times (3 \times 10^8 \, \text{m/s})}{6.6 \times 10^{-34} \, \text{Js}} \]

4. **Calculating the numerator**:
First, calculate the numerator:
\[ 3.3 \times 10^{-29} \times 3 \times 10^8 = 9.9 \times 10^{-21} \]

5. **Calculating the frequency**:
Now, divide the result by \( h \):
\[ \nu = \frac{9.9 \times 10^{-21}}{6.6 \times 10^{-34}} = 1.5 \times 10^{13} \, \text{Hz} \]

### Final Answer:
The frequency of the radiation is \( \nu = 1.5 \times 10^{13} \, \text{Hz} \).

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