In an experiment on photoelectric effect the frequency `f` of the incident light is plotted against the stopping potential `V_(0)`. The work function of the photoelectric surface si given by ( e is the electronic charge)

Options

A. OB `xx` e in eV
B. OB in volt
C. OA in eV
D. the slope of the line AB

Answer

A

Explanation

From Einstein's photoelectric equation
`K_("max")=hv-hv_(0)`
`:.eV_(0)=hv-hv_(0)=hv-W_(0)`
`:.V_(0)=(h/e)v-(W_(0)/(e))`
Comparing with the equation `y=mx +c`
we find that the slope `=h/e`
and intercept on the `-V_(0)` axis`=(W_(0))/(e)=OB`
`:.OB=(W_(0))/(e)` or `W_(0)=OBxx e` (in eV)