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The energy of a photon of wavelength lam...

The energy of a photon of wavelength `lambda` is [ h = Planck's constant, c = speed of light in vacuum ]

A

`hclambda`

B

`(h lambda)/(c)`

C

`(lambda)/(hc)`

D

`(hc)/(lambda)`

Text Solution

Verified by Experts

The correct Answer is:
D
For the photon, `E=hv=(hc)/(lambda)`.
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Knowledge Check

  • The energy of photon of wavelength lambda is ……………….. . [h = Plancks constant, c = speed of light in vacuum]

    A
    `hclambda`
    B
    `(hlambda)/(c )`
    C
    `(lambda)/(hc)`
    D
    `(hc)/(lambda)`

  • The energy of a photon of wavelength lambda is given by

    A
    `hlambda`
    B
    `chlambda`
    C
    `lambda/"hc"`
    D
    `"hc"/lambda`

  • The energy of a photon in eV of wavelength lambda nm will be

    A
    `E(eV) =(1242)/(lambda(nm))`
    B
    `E(eV) =(1000)/(lambda(nm))`
    C
    `E(eV) =(500)/(lambda(nm))`
    D
    `E(eV) =(250)/(lambda(nm))`

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