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A body of mass 5sqrt(3) kg is acted upon...

A body of mass `5sqrt(3)` kg is acted upon by two forces each of magnitude 2 N and inclinded at `60^(@)` with each other. What is the acceleration of the body in `m//s^(2)` ?

A

1.5

B

0.5

C

0.4

D

0.8

Text Solution

Verified by Experts

The correct Answer is:
C
By the law of parallelogram of forces
`R^(2) = P^(2) +Q^(2) + 2PQ cos theta" where "theta =60^(@)`
`therefore F^(2) =4+4+2xx2xx2xx(1)/(2) =8+4=12`
`therefore F= sqrt (12) =2sqrt(3) N`
`therefore a = (F)/(m) =(2sqrt(3))/(5sqrt(3))=(2)/(5) = 0.4 m//s^(2)`
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