The magnitude of the vector product of two vectors is `sqrt(3)` times their scalar product. The angle between the two vectors is

Options

A. `30^(@)`
B. `45^(@)`
C. `60^(@)`
D. `90^(@)`

Answer

C

Explanation

`|vec P xx vec Q| = PQ sin theta and vec P cdot vec Q = PQ cos theta`
`because PQ sin theta = sqrt(3) PQ cos theta`
`therefore (sin theta)/(cos theta) = tan theta = sqrt(3)" "therefore theta =60^(@)`
`[because (sin 60^(@))/(cos 60^(@))=(sqrt(3)//2)/(1//2)= sqrt(3)]`