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The units of molar conductance are...

The units of molar conductance are

A

`"mole"^(-1) "cm"^(+1) "ohm"^(-1)`

B

`"ohm"^(-1) "cm"^(2) "mole"^(+1)`

C

`"ohm"^(-1) "cm"^(2) "mole"^(+1)`

D

`"ohm"^(-1) "dm"^(3) "mole"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`"Ohm"^(-1)=S`
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Knowledge Check

  • The unit of molar conductance of an electrolyte solution will be

    A
    `ohm^(-1)` cm `mol^(-1)`
    B
    mho `cm^2` `mol^(-1)`
    C
    ohm `cm^(2)` `mol^(-1)`
    D
    `ohm^(-1)` `cm^(-1)` `mol^(-1)`

  • At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated. the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions. A_(x)B_(y) rarr xA^(y+)+yB^(x-) Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@) where, x and y are the number of cations and anions respectively. The degree of ionisation 'alpha' of weak electrolyte can be calculated as : alpha=Lambda_(m)/Lambda_(m)^(@) The unit of molar conductance of an electrolyte solution will be :

    A
    `ohm^(-1) cm^(2) mol^(-1)`
    B
    mho `cm^(2) mol^(-1)`
    C
    `S cm^(2) mol^(-1)`
    D
    `ohm^(-1) cm^(-1) mol^(-1)`

  • Molar conductance of a solution is given by the expression ^^m = (kxx1000mLL^(-1))/(c) Here c is the concentration in mol L^(-1) and k is expressed in ohm^(-1) cm^(-1) . Units of molar conductance are

    A
    `ohm mol^(-1)`
    B
    `Ohm cm^(-1) mol^(-1)`
    C
    `ohm cm^(2) mol`
    D
    None of these

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