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The specific conductance of a 0.12 N sol...

The specific conductance of a 0.12 N solution of an electrolyte is `2.4xx10^(-2) S cm^(-1)`. Calculate its equivalent conductance.

A

100

B

50

C

200

D

40

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda=(1000K)/(c)=(1000xx0.024)/(0.12)=200`
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