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Calculate the molar conductivity of a so...

Calculate the molar conductivity of a solution of NaCl at infinite dilution. Given
`lambda^(oo)(Na^(+))=50.11 "ohm"^(-1)cm^(2)mol^(-1)`
`lambda^(oo)(Cl^(-))=76.34 "ohm"^(-1)cm^(2)mol^(-1)`

A

`126.45 "ohm"^(-1)cm^(2)mol^(-1)`

B

`127.45"ohm"^(-1)cm^(2)mol^(-1)`

C

`125.45"ohm"^(-1)cm^(2)mol^(-1)`

D

`100.22"ohm"^(-1)cm^(2)mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`^^_(NaCl)^(oo)=lambda^(oo)Na+lambda_(Cl^(-))^(oo)`
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