At 298K the resistance of a 0.5N NaOH so...

At 298K the resistance of a 0.5N NaOH solution is 35.0 ohm. The cell constant is 0.503 `cm^(-1)` the electrical conductivity of the solution is

`1.473xx10^(-2) "ohm"^(-1)cm^(-1)`

`1.473 "ohm"^(-1)cm^(-1)`

`14.73 "ohm"^(-1)cm^(-1)`

`0.1473 "ohm"^(-1)cm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:

`K=b/R`

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