The specific conductance of N/50 solutio...

The specific conductance of N/50 solution of KCl at `25^(@)C` is 0.2765 `"ohm"^(-1)` . If the resistance of the cell containing this solution is 400 ohms , then the cell constant is

`11.06 cm^(-1)`

`.000066 cm^(-1)`

`1.106 cm^(-1)`

`110.6 cm^(-1)`

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The correct Answer is:

b=KR

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