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A current of 0.75 A is passed through an...

A current of `0.75 A` is passed through an acidic solution of `CuSO_4` for `10` minutes. The vlume of oxygen liberated at anode (at STP) will be.

A

`0.243 dm^(3)`

B

`0.243 m^(3)`

C

0.243 `cm^(3)`

D

24.3 mL

Text Solution

Verified by Experts

The correct Answer is:
D

Numbers of coulombs =`0.75 xx10xx60 =420C`
`96,500C-=8 g -=5.6 dm^3 of O_2`
`therefore 420C -= (5.6xx420)/(96,500) =0.0243 dm^3`
`=0.0243xx1000 =24.3 cm^3`
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