The number of atoms of Cr discharged from `CrCl_(3)` solution by passage of 1.5 faraday would be

Options

A. `6 xx 10^(23)`
B. `3 xx 10^(23)`
C. `2 xx 10^(20)`
D. `6 xx 10^(10)`

Answer

B

Explanation

3 Faraday -= 1 mole of `Cr(Cr^(+3))`
`therefore 1.5 " Faraday "-=(1)/(2) " mole of "Cr = 3xx10^(23)`