In the cell reaction
`Ag_((s))+Cu(aq))^(2+)+Br_((aq))^(-) to AgBr_((s))+Cu_((s))`
the reduction half reaction is

Options

A. `Ag_((s)) to Ag^(+)+e^(-)`
B. `Cu^(2+)+2e^(-) to Cu`
C. `Cu to Cu^(2+)+2e^(-)`
D. `Ag_((s))+Br_((aq))^(-) to AgBr_((s))+e^(-)`

Answer

B

Explanation

`2Ag(s) to 2Ag_((aq))^(+)+2e^(-)`
`Cu^(2+)+2e^(-) to Cu`