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For the cell Zn|Zn^(+2)||Cu^(+2)|Cu, if ...

For the cell `Zn|Zn^(+2)||Cu^(+2)|Cu`, if the concentration of `Zn^(+2)` and `Cu^(+2)` ions is doubled, the emf of the cell

A

doubles

B

reduces to half

C

remains same

D

becomes zero

Text Solution

Verified by Experts

The correct Answer is:
C

Ration of log`[Zn^(2+)]/[Cu^(2+)]` remain same.
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