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If standard electrode potenial of Cu^(2+...

If standard electrode potenial of `Cu^(2+)//Cu` is `0.34V` then potential of `Cu` dipped in 0.1 M solution of `CuSO_(4)` will be

A

0.34 V

B

`-0.34 V`

C

0.31 V

D

`-0.31 V`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=E^(0)-(0.059)/(n) log_(10)[Cu^(+2)]`
=`0.34-(0.059)/(2)log_(10)""(1)/(0.1) =0.31`
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