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The cell potential of the galvanic cell ...

The cell potential of the galvanic cell
`Zn|Zn^(++)|Ag^(+)|Ag` ,
`E^(@)(Zn^(++)|Zn)=-0.76 V, E^(@)(Ag^(+)|Ag)=+0.80 V`

A

`+ve`

B

`-ve`

C

zero

D

can't say

Text Solution

Verified by Experts

The correct Answer is:
A

`E_(cell)^(0)=underset(Ag)E_("cathode")^(0)-underset(Zn)E_("anode")^(0)=1.56 V`
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