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How many faraday are required to liberat...

How many faraday are required to liberate 8 g of hydrogen ?

A

2

B

4

C

8

D

18

Text Solution

AI Generated Solution

The correct Answer is:
To determine how many Faraday are required to liberate 8 g of hydrogen, we can follow these steps: ### Step 1: Understand the Reaction The liberation of hydrogen gas (H2) from hydrogen ions (H+) involves a reduction reaction where H+ ions gain electrons. The balanced half-reaction can be represented as: \[ 2H^+ + 2e^- \rightarrow H_2 \] This shows that 2 moles of electrons are required to produce 1 mole of hydrogen gas. ### Step 2: Calculate the Molar Mass of Hydrogen The molar mass of hydrogen (H2) is calculated as follows: - The atomic mass of hydrogen (H) is approximately 1 g/mol. - Therefore, the molar mass of H2 is: \[ 2 \times 1 \, \text{g/mol} = 2 \, \text{g/mol} \] ### Step 3: Determine the Moles of Hydrogen Next, we need to find out how many moles of hydrogen correspond to 8 g: \[ \text{Moles of } H_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{8 \, \text{g}}{2 \, \text{g/mol}} = 4 \, \text{mol} \] ### Step 4: Calculate the Moles of Electrons Required From the balanced reaction, we know that to produce 1 mole of H2, 2 moles of electrons are required. Therefore, for 4 moles of H2: \[ \text{Moles of electrons} = 4 \, \text{mol H}_2 \times 2 \, \text{mol e}^- / \text{mol H}_2 = 8 \, \text{mol e}^- \] ### Step 5: Convert Moles of Electrons to Faraday 1 mole of electrons is equivalent to 1 Faraday. Therefore, the number of Faraday required to liberate 8 moles of electrons is: \[ \text{Faraday required} = 8 \, \text{mol e}^- \times 1 \, \text{Faraday/mol e}^- = 8 \, \text{Faraday} \] ### Final Answer Thus, to liberate 8 g of hydrogen, **8 Faraday** are required. ---

To determine how many Faraday are required to liberate 8 g of hydrogen, we can follow these steps: ### Step 1: Understand the Reaction The liberation of hydrogen gas (H2) from hydrogen ions (H+) involves a reduction reaction where H+ ions gain electrons. The balanced half-reaction can be represented as: \[ 2H^+ + 2e^- \rightarrow H_2 \] This shows that 2 moles of electrons are required to produce 1 mole of hydrogen gas. ...
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