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When 0.25 mol I^(-) oxidised in IO(3)^(-...

When `0.25 mol I^(-)` oxidised in `IO_(3)^(-)` then what coulomb of electric charge related with the reaction theoretically ?

A

`5.79 xx 10^(5)C`

B

`4.82500 xx 10^(5)C`

C

`2.895 xx 10^(5)C`

D

`1.4475 xx 10^(5)C`

Text Solution

Verified by Experts

The correct Answer is:
D
`I^(-) to IO_(3)^(-), I^(+5)+6e^(-)`
`therefore` 1 mole =6F `therefore 0.25 =6Fxx0.25=1.5 F`
`therefore 1.5 xx 96500 C=144750n C=1.4475 xx 10^(5) C`
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