Calculate the equilibrium constant for the reaction at 298 K
`Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)`
Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`

Options

A. 3.3791
B. `1.9413 xx 10^(37)`
C. `4.406 xx 10^(18)`
D. `5.15 xx 10^(-38)`

Answer

B

Explanation

`Zn+Cu^(2+) to Cu + Zn^(2+)`
`E_(Zn^(2+)//Zn)^(0) =-0.76, E_("Cu^(2+)//Cu)^(0) =0.34 V` ltbr? `=0.36-(-0.76)=1.1 V`
`E_("cell")^(0)=(0.059)/(n)log KC`
`therefore log KC =(2.2)/(0.059)=37.2881`
`therefore KC =1.9413 xx 10^(37)`