For the electrochemical cell, `(M)|M^(+))||(X^(-)|X)`.
`E^(@)(M^(+)//M)=0.44V` and `E^(@)(X//X^(-))=0.33V`.
From this data one can deduce that

Options

A. `M+X too M^(+)+X^(-)` is the spontaneous reaction
B. `M^(+)+X^(-) too M +X` is the spontaneous reaction
C. `E_(cell) = 0.77 V`
D. `E_(cell) = -0.77 V`

Answer

B

Explanation

`M^(+)+X^(-) to M+X` is spontaneous because for the cell represented by `M|M^(+)||X^(-)|X`, the value of `E^(@)` is positive
i.e.(0.44-0.33)V =0.11V.