The number of electrons required to reduce `4.5 xx 10^(–5)` g of `Al^(+3)` is :

Options

A. `3.01 xx 10^(18)`
B. `6.02 xx 10^(18)`
C. `2.90 xx 10^(18)`
D. `3.01 xx 10^(19)`

Answer

A

Explanation

Reduction reaction : `Al_((aq))^(+3) +3e^(-) to Al_((s))` 27 g of `Al^(+3)` required for reduction 3F of electricity . Therefore, `4.5 xx10^(-5) Al^(+3)` will require `0.5xx10^(-5)` F electrons. Therefore, `0.5xx10^(-5)` F of electricity is `3.011 xx 10^(18)` electrons.