SRP of `Sn^(2+)//Sn^(4+)` is 0.5 , SRP of `Au//Au^(3+)` is 1.5, give reaction for the cell

Options

A. `2Sn^(2+)+3Au^(3+) to 2Sn^(4+)+3Au`
B. `3Sn^(2+)+2Au^(3+) to 3Sn^(4+)+2Au`
C. `2Sn^(4+)+3Au to 2Sn^(2+) +3Au^(3+)`
D. `3Sn^(4+)+2Au to 3Sn^(2+)+2Au^(3+)`

Answer

B

Explanation

SRP of `Au//Au^(3+) gt` SRP of `Sn^(2+)//Sn^(4+)`.
Therefore `Au^(+3)` undergo reduction and `Sn^(2+)` undergo oxidation.