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For the reaction , H(2(g))+Hg(2)Cl(2) ...

For the reaction ,
`H_(2(g))+Hg_(2)Cl_(2) to 2Hg_((l))+2HCl_((aq))`
electrochemical cell will be:

A

`Pt,H_(2)|HCl||`Calomel electrode

B

`Hg|Hg(NO_(3))_(2)||`Calomel electrode

C

Calomel electrode`||HCl|H_(2)_((g)), Pt`

D

`Hg|Hg_(2)Cl_(2),KCl||Hg(NO_(3))_(2)|Hg`

Text Solution

Verified by Experts

The correct Answer is:
A
Large difference in SOP gives spontaneous cell reaction.
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For the reactions, (i) H_(2)(g)+Cl_(2)(g)=2HCl(g)+xkJ (ii) 2HCl(g)=H_(2)(g)+Cl_(2)(g)-ykJ Which one of the following statements is correct?

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