How many coulombs are required for the oxidation of 0.01 mol of `H_(2)O to O_(2)` ?

Options

A. `1.93 xx 10^(3) C`
B. `9.65 xx 10^(2) C`
C. `3.86 xx 10^(5) C`
D. `4.285 xx 10^(2) C`

Answer

A

Explanation

In the electrolysis of dil. `H_(2)SO_(4)` the electrolysis takes place as
`H_(2)O hArr H^(+)+OH^(-)`
At anode `" " 2OH^(-) to H_(2)O+[O]+2e^(-)`
At cathode `" " 2H^(+)+2e^(-) to 2[H]`
`therefore W+[O]:W+2[H^(+)] therefore 16:2 therefore 8:1`